大學year 1 math,,help

For what value of the constants a and b such that the following limit exists?

lim      {(ax+|x+1|)|x+b-2|}/|x+1|
x->-1   


help me ,thx

bjl1212

write x=-1+h and simplify it "a" could be anything but b=-3

gm73739

Answer:
1) a = 0 and b can be any real number
or
2) b=3 and a can be any real number

-----------------------------------------------------------------------------------------------------------Solution:
Let f(x)={(ax+|x+1|)|x+b-2|}/|x+1|
The denominator of f(x) becomes 0 as x approaches -1.
Since division by zero is an undefined number, we can not evaluate the limit of f(x).

For the limit to exist, the denominator in f(x) has to be removed after simplification.
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gm73739 發表於 2016-2-19 01:16 AM

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Answer:
1) a = 0 and b can be any real number
or

thx you><
                          ...

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