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| Answer:
1) a = 0 and b can be any real number
or
2) b=3 and a can be any real number
-----------------------------------------------------------------------------------------------------------Solution:
Let f(x)={(ax+|x+1|)|x+b-2|}/|x+1|
The denominator of f(x) becomes 0 as x approaches -1.
Since division by zero is an undefined number, we can not evaluate the limit of f(x).
For the limit to exist, the denominator in f(x) has to be removed after simplification. ... |
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